下列代码中,d1->work(); 和 d2->work(); 输出不同结果的主要原因是( )。
class Device {
public:
virtual void work() {
cout << "Device is working" << endl;
}
virtual ~Device() {}
};
class Printer : public Device {
public:
void work() override {
cout << "Printer is printing" << endl;
}
};
class Scanner : public Device {
public:
void work() override {
cout << "Scanner is scanning" << endl;
}
};
int main() {
Device* d1 = new Printer();
Device* d2 = new Scanner();
d1->work();
d2->work();
delete d1;
delete d2;
return 0;
}
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