下面程序的运行结果为（ ）。
def query(n, a, x):
left = 0
right = n
while left < right:
mid = left + (right - left) // 2
if a[mid] >= x:
right = mid
else:
left = mid + left
if left == n:
return -1
return left
if __name__ == "__main__":
n = 10
x = 3
num = [1, 2, 2, 3, 3, 4, 5, 5, 6, 7]
result = query(n, num, x)
print(result)
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