判断给定C++代码构建的树是否一定为完全二叉树
下面代码构建的树一定是完全二叉树：
struct TreeNode {
int value;
TreeNode* left;
TreeNode* right;
};
TreeNode* buildCompleteBinaryTree() {
TreeNode* root = new TreeNode{1};
root->left = new TreeNode{2};
root->right = new TreeNode{3};
root->left->left = new TreeNode{4};
root->left->right = new TreeNode{5};
root->right->left = new TreeNode{6};
return root;
}
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